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2x^2+45x-47=0
a = 2; b = 45; c = -47;
Δ = b2-4ac
Δ = 452-4·2·(-47)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-49}{2*2}=\frac{-94}{4} =-23+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+49}{2*2}=\frac{4}{4} =1 $
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